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6h^2+68h+22=0
a = 6; b = 68; c = +22;
Δ = b2-4ac
Δ = 682-4·6·22
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-64}{2*6}=\frac{-132}{12} =-11 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+64}{2*6}=\frac{-4}{12} =-1/3 $
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